How much of a 0.23 M NaOH solution is needed to neutralize 27 mL of a 0.85 M sulfuric acid solution? The units are mL.

Question

Can you please explain why you did what did

Thank you

Answer 1

well, it takes two moles of NaOH to neutralize on mole of sulfuric acid, so

2*.23(Volumebase)=27ml*.85
solve for volumebase