How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)?

Question

KE=12mv2
(1 point)
Responses

151.2 J
151.2 J

35.9 J
35.9 J

1.3 J
1.3 J

266.5 J

Answer 1

To calculate the kinetic energy, we can use the formula KE = 1/2 * m * v^2.

For the first case, with a mass (m) of 6 kg and velocity (v) of 7.1 m/s:
KE1 = 1/2 * 6 kg * (7.1 m/s)^2
KE1 = 1/2 * 6 kg * 50.41 m^2/s^2
KE1 = 151.23 J

For the second case, with a mass (m) of 6 kg and velocity (v) of 6.2 m/s:
KE2 = 1/2 * 6 kg * (6.2 m/s)^2
KE2 = 1/2 * 6 kg * 38.44 m^2/s^2
KE2 = 115.32 J

The difference in kinetic energy (KE) between the two cases is:
KE1 - KE2 = 151.23 J - 115.32 J
KE1 - KE2 = 35.91 J

Therefore, the bowling ball has 35.91 J more kinetic energy when rolling at 16 mph compared to when rolling at 14 mph.