How much more kinetic energy does a 6-kilogram bowling ball have when it’s rolling at 16 mph 7.1 meters per second than when it is rolling at 14mph 6.2 meters per second

Answer 1

To solve this problem, we need to use the formula for kinetic energy:

KE = 0.5 * m * v^2

where KE is the kinetic energy, m is the mass, and v is the velocity.

First, let's find the kinetic energy of the bowling ball when it's rolling at 16 mph:

KE1 = 0.5 * 6 kg * (7.1 m/s)^2
KE1 = 151.41 J

Now, let's find the kinetic energy of the bowling ball when it's rolling at 14 mph:

KE2 = 0.5 * 6 kg * (6.2 m/s)^2
KE2 = 113.04 J

The difference in kinetic energy is:

ΔKE = KE1 - KE2
ΔKE = 151.41 J - 113.04 J
ΔKE = 38.37 J

Therefore, the bowling ball has 38.37 more joules of kinetic energy when it's rolling at 16 mph compared to when it's rolling at 14 mph.