How much mole of dry hydrogen at NTP is liberated on heating 0.1 mole of Mg with excess of dilute HCl? Actually what is NTP? I know the balaned equation and 1mole Mg forms 1 mole H2 , then 0.1 mole forms 1/0.1 moles of H2? Plz help

Question

How much mole of dry hydrogen at NTP is liberated on heating 0.1 mole of Mg with excess of dilute HCl? Actually what is NTP? I know the balaned equation and 1mole Mg forms 1 mole H2 , then 0.1 mole forms 1/0.1  moles of H2?  Plz help

DrBob222 · Answer

Almost. Since
Mg + 2HCl ==> H2 + MgCl2
then 0.1 mol Mg will form 0.1 mol H2. Now convert that to NTP. STP is 0 degrees C (273 kelvin) and 1 atm pressure. NTP is 20 C (293 kelvin) and 1 atm pressure.

Is this a trick question? 0.1 mol Mg metal will produce 0.1 mol dry H2 (or wet H2 for that matter but it will have water added in with it) no matter what the conditions. NTP, STP, SATP, etc will change the VOLUME of 0.1 mol gas but it won't change the amount in grams of the gas; i.e., 0.1 mol H2 will be 0.1 mol x 2g/mol = 0.2 gram no matter how you slice it.