To find out how much longer the length of the envelope is than its width, you can subtract the width from the length.
The length is 9 1/2 inches, and the width is 4 1/8 inches.
First, let's convert both measurements to improper fractions for easier subtraction:
-
Length (9 1/2): \[ 9 \frac{1}{2} = \frac{9 \times 2 + 1}{2} = \frac{18 + 1}{2} = \frac{19}{2} \]
-
Width (4 1/8): \[ 4 \frac{1}{8} = \frac{4 \times 8 + 1}{8} = \frac{32 + 1}{8} = \frac{33}{8} \]
Now, we need a common denominator to subtract these two fractions. The common denominator of 2 and 8 is 8.
Convert \(\frac{19}{2}\) to a fraction with a denominator of 8: \[ \frac{19}{2} = \frac{19 \times 4}{2 \times 4} = \frac{76}{8} \]
Now we can subtract the width from the length: \[ \frac{76}{8} - \frac{33}{8} = \frac{76 - 33}{8} = \frac{43}{8} \]
Now, let's convert \(\frac{43}{8}\) back to a mixed number: \[ \frac{43}{8} = 5 \frac{3}{8} \]
So, the length of the envelope is \(5 \frac{3}{8}\) inches longer than its width.
2 answers