How much ice at zero degrees Celcius (in grams) would have to melt to lower the temperature of 351 of water from 25 to 5? (Assume the density of water is 1.0 .)

Answer 1

can not do this without units

Answer 2

x = grams of ice

x times heat of fusion of water in cal/gram = grams of water * specific heat of water in cal/deg gm * (25-5)

Answer 3

x = grams of ice

x times heat of fusion of water in cal/gram = grams of water * specific heat of water in cal/deg gm * (25-5)
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That assumes that the ice is separated from the water. If they mix then the ice not only has to melt but also be raised from 0 to 5. Then:

x = grams of ice

x times heat of fusion of water in cal/gram + x *specific heat of water * (5-0) = grams of water * specific heat of water in cal/deg gm * (25-5)