How much heat must be removed from 0.20kg of water at 10.0oC to form ice at 0oC?

Answer 1

q1 = heat removed to lower T from 10C to zero C.
q1 = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q1 = 200g x 4.184 x (10) = ?

q2 = heat removed to freeze the H2O (change from liquid to solid phase).
q2 = mass H2O x heat fusion H2O.
q2 = 200 x heat fusion = ?

Look up heat fusion, then total heat removed is q1 + q2