heat=mass*specificheatcapacity*changeinTemp
heat=90*c*(100C-0C)
look up the value of specific heat c, and you have it.
How much heat is required to raise the temperature of 90.0g of water from its melting point to its boiling point?
Can someone please help me set this up, I am so confused
2 answers
All of these are worked with that magical formula of
q = mc*delta T
q = 90 x specific heat H2O x (Tfinal-Tinitial)
specific heat H2O is 4.184 J/g*C
Tf = 100
Ti = 0
q = mc*delta T
q = 90 x specific heat H2O x (Tfinal-Tinitial)
specific heat H2O is 4.184 J/g*C
Tf = 100
Ti = 0
1 answer