I think Bob Pursley worked this problem for you but you don't give all of the data needed here. Here is how to do it.
q1 = heat to move CH3OH from 20 to 30.
q1 = mass CH3OH x spcific heat CH3OH x (delta T).
q2 =heat to vaporize CH3OH at 30.
q2 = mass CH3OH x heat of vaporization at 30.
Then total heat = q1 + q2.
I must point out that CH3OH boils at about 65 or so so the usual heat of vaporization at 65 may not be the same as the heat of vaporization at 30. If the information in your original post was not the same then he may have worked the problem somewhat differently.
How much heat is required to raise the temperature of 200 g CH3OH from 20 to 30 degrees and then vaporize it at 30 degrees. The molar heat capacity of CH3OH is 81.1 J/Mol/K.
Okay...the answer is approximately around 254. It was a homework problem. The question is how do you get to the answer? I had someone give me the answer, but I want to know how to do it. So can anyone just show me the steps to get to the answer.
3 answers
hm...I don't remember posting this problem but thank you again dr.bob, I can definetly always count on you
Btw what do I do about the molar heat capacity