How much heat is required to melt 75.5g of ice at -25 degrees Celcius, and convert it to steam at 105 Celcius

Answer 1

q1=heat to move ice from -25 to zero C. (Not the correct spelling of celsius).
q1 = mass ice x specific heat ice x (Tfinal-Tinitial). Tfinal = zero and Tinitial = -25

q2 = heat to melt ice at zero to liquid water at zero c.
q2 = mass ice x heat fusion

q3 = heat to move water from zero C to 100 C.
q3 = mass x specific heat water x (Tfinal-Tinitial). Tfinal is 100 and Tinitial is zero.

q4 = heat to turn water at 100 C to steam at 100.
q4 = mass water x heat vaporization.

q5 = heat to move steam from 100 C to 105 C.
q5 = mass steam x specific heat steam x (Tfinal-Tinitial)

Total heat required is
q1 + q2 + q3 + q4 + q5.
Post your work if you get stuck.

Answer 2

45678j/c