It is wrong.
figure
a. heat to heat ice to 0C from -11.5
Note: there is no reason to conver to K. One kelvin change is exactly one C change.
Then heat to melt the ice at 0C
then to heat the water from 0 C to 52 C
add them up.
How much heat is required to convert solid ice with a mass of 875 g and at a temperature of -11.5 °C to liquid water at a temperature of 52.0 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)
I did -> (.875)(2100)(325-261.5) = 116681J
then (.875)(334000)= 292250J
then added those two answers together and got 408931J and it keeps saying that is wrong..
1 answer