How much heat is required to completely boil away 0.200 kg of water (Hv = 2.26 × 10^3 kJ/kg)?
(Points : 1)
4.52 × 102 kJ
2.26 × 103 kJ
4.52 × 103 kJ
1.13 × 104 kJ
4 answers
nvm.. i found this one out...
what was it
Correct answers
In which labeled portion of the curve would you use the heat of vaporization to calculate the heat absorbed?
- 4
How much heat does it take to melt 2.5 kg of lead when it is at it's melting point?
- 5.1 X 10^1 J
It takes 2.52 x 10^5 J of heat to melt 4.00 kg of substance. According to the table what is the substance?
- gold
Which of the following would you use to calculate the heat released when a liquid freezes?
Heat of solidification
How much heat is required to completely boil away 0.200 kg of water
- 4.52 x 10^2 kJ
How much heat does it take to vaporize 50.0 g of water?
- 1.23 x 10^5 J
Done 6/6
In which labeled portion of the curve would you use the heat of vaporization to calculate the heat absorbed?
- 4
How much heat does it take to melt 2.5 kg of lead when it is at it's melting point?
- 5.1 X 10^1 J
It takes 2.52 x 10^5 J of heat to melt 4.00 kg of substance. According to the table what is the substance?
- gold
Which of the following would you use to calculate the heat released when a liquid freezes?
Heat of solidification
How much heat is required to completely boil away 0.200 kg of water
- 4.52 x 10^2 kJ
How much heat does it take to vaporize 50.0 g of water?
- 1.23 x 10^5 J
Done 6/6
comment above is all correct ^^^
0 answers