How much heat is needed to bring 120 g of water from 33C to 45C
2 answers
q=mc∆t=(120g)(4.186 J/g•C°)(45C-35C)
q=mc∆t=(120g)(4.186 J/g•C°)(45C-33C)
Typo 33 not 35
Typo 33 not 35
2 answers