How much heat (in kJ) is evolved in converting 1.00 mol of steam at 130.0 C to ice at -50.0 C? The heat capacity of steam is 2.01 J/g*C and of ice is 2.09 J/g*C.

Answer 1

You must go through all of the steps from steam at 130 to ice at -50.
q to move steam at 130 to steam at 100.
q1 = mass x specific heat x delta T.

q to convert steam at 100 to liquid water at 100.
q2 = mass x heat of vaporization.

q to move water at 100 to water at zero.
q3 = mass x specific heat x delta T.

q to convert water at zero to ice at zero.
q4 = mass x heat of fusion.

q to move ice at zero to ice at -50.
q5 = mass x specific heat x delta T.

Then total q =
q1+q2+q3+q4+q5.
I notice your specific heats are listed in joules so your answer will come out in Joules and you must convert to kJ since the problem asks for kJ.

Answer 2

55.078

Answer 3

57 kj