4.10 g Al = how many mols?
4.10/27 (look up the value) = ??
You get 1408.4 kJ/mol so how much will you get for ?? mole?
Didn't you post a question earlier asking how to prepare a solution of 471 g acetone + solvent (the question was for the solvent)? I posted an answer and now I can't find the question or the answer.
How much heat (in kilojoules) is released on reaction of 4.10 g of Al?
Reaction: 2Al(s) + 3Cl2(g)--->2AlCl3(s)
Delta H= -1408.4 KJ
3 answers
no i didn not. but thank you!
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