How much heat evolves when 275 g of ammonia gas condenses to a liquid at its boiling point?

1 answer

To determine the amount of heat evolved when ammonia gas condenses to a liquid at its boiling point, we need to know the heat of vaporization of ammonia. The heat of vaporization of ammonia is given as 23.35 kJ/mol.

To calculate the heat evolved, we first need to convert the mass of ammonia from grams to moles. The molar mass of ammonia (NH3) is 17.03 g/mol.

Number of moles of ammonia = mass / molar mass
Number of moles of ammonia = 275 g / 17.03 g/mol ≈ 16.13 mol

Now, we can calculate the heat evolved using the heat of vaporization:

Heat evolved = number of moles × heat of vaporization
Heat evolved = 16.13 mol × 23.35 kJ/mol ≈ 376.5 kJ

Therefore, approximately 376.5 kJ of heat evolves when 275 g of ammonia gas condenses to a liquid at its boiling point.