How much force must be exerted at the right end to pick up the lever and load if it pivots at the left end? The 2.00 meter long lever weighs 1.50 N and is uniform. There is an 8.00 N weight resting on the 40.0 cm mark.
so would it take .4m (40cm to m)
.4m*8N=32Nm=?1.6M
because 1.6 is the distance left over 2.0-.4=1.6??
so 3.2/1.6=2N?
1 answer
f * 2.00 m = (8.00 N * 0.400 m) + [(2.00 m / 2) * 1.50 N]
4 answers