how much force is required to stop a 100 mi/hr fastball? assume the catcher's mitt stops the ball in 1 millisecond and the mass of a baseball is 145 g

Answer 1

V=100mi/h * 1600m/mi * 1h/3600s =
44.44m/s

V = Vo + a*t = 0
a = -Vo/t = -44.444/10^-3=-44,444 m/s^2

F = m*a = 0.145 * (-44,444) = - 6444 N.