v = omega r
dv = omega dr
omega = 2 pi radians/(24*3600)seconds
dr = 18.2
dv = 2 pi (18.2) /(24*3600)
How much faster would a person be moving if they stood on top of a 18.2 m high building compared to the ground? Take the period to be one day, and the radius of the earth to be 6400 km?
1 answer