40 g = .04 kg
.04 [25 (sh ice) + heat of fusion + 100 (sh water) + heat of vaporization + 5 (sh water vapor at 1 atm) ]
How much energy is required to change a 40 g ice cube from ice at -25°C to steam at 105°C?
2 answers
I don't know if this is right that i pulled in..but i got it wrong. Please help.
4(2090)+(3.33⋅10^5 )+100(4186)+(2.26⋅10^6)+5(4186)
4(2090)+(3.33⋅10^5 )+100(4186)+(2.26⋅10^6)+5(4186)
1 answer