The combustion of ethylene (C2H4) releases 1.36 x 10^4 kJ/mol of energy.
To calculate the energy released when 23.0 g of ethylene reacts, we first need to determine the number of moles of ethylene in 23.0 g:
Molar mass of ethylene (C2H4) = 2*12.01 + 4*1.008 = 28.05 g/mol
Number of moles = 23.0 g / 28.05 g/mol = 0.821 mol
Now, we can calculate the energy released:
Energy released = 0.821 mol * 1.36 x 10^4 kJ/mol = 1.11 x 10^4 kJ
Therefore, the energy released when 23.0 g of ethylene reacts is 1.11 x 10^4 kJ, with 3 significant figures.
How much energy is released when 23.0 of ethylene reacts? Be sure your answer has the correct number of significant figures.
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