How much energy does it take to convert 750 grams of ice at 0 degrees Celsius to liquid water at 40 degrees Celsius? (Specific Heat of water = 4.18 J/g*C and the heat of fusion = 334 J/g)

Answer 1

To melt the ice is q1 = mass ice x heat fusion.
To raise T from zero to 40 C is
q2 = mass water x specific heat water x 40
Total is sum q1 + q2.

Answer 2

the

Answer 3

399