Qout = Qin + Win
Qin = Qout - Win
= Qout - Qout/3.85
= 0.7403 Qout
Use your previously caclulated value of Qout, which was correct. Scientific notation would be preferable
How much energy does it extract from the outside air with coefficient of performance 3.85?
A heat pump has a coefficient of performance of 3.85 and operates with a power consumption of 6.91 x 10^3 W.
The first part of the question asked How much energy does it deliver into a home during 8 h of continuous operation? and I got 766180800 J.
I need help on the last part which asks How much energy does it extract from the outside air? answer in Joules.
2 answers
I got lost when you got to:
= Qout - Qout/3.85
= 0.7403 Qout
What did you exactly do? I'm not seeing where those two Qout's came from and how you got the .7403.
= Qout - Qout/3.85
= 0.7403 Qout
What did you exactly do? I'm not seeing where those two Qout's came from and how you got the .7403.