How much current is in a circuit that includes a 9.0-volt battery and a bulb with a resistance of 4.0 ohms?

Question

A.
0.44 amps
B.
36 amps
C.
2.3 amps
D.
13 amps

Answer 1

To calculate the current in a circuit using Ohm's Law, we can use the formula:

\[ I = \frac{V}{R} \]

where:

• \( I \) is the current (in amps),
• \( V \) is the voltage (in volts), and
• \( R \) is the resistance (in ohms).

In this case, we have:

• \( V = 9.0 \) volts,
• \( R = 4.0 \) ohms.

Now, we can substitute in the values:

\[ I = \frac{9.0 , \text{V}}{4.0 , \Omega} = 2.25 , \text{A} \]

Rounding to two decimal places, the current is approximately \( 2.3 \) amps.

Therefore, the correct answer is C. 2.3 amps.