To estimate how many chocolates you can fit in a 1600 mL jar, we'll need to first consider the average volume of each type of candy mentioned (Aero, KitKat, Skittles).
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Average volume of candies:
- Aero: Approximately 10-15 mL per piece (let's take an average of 12.5 mL)
- KitKat: Approximately 10-15 mL per piece (let's take an average of 12.5 mL)
- Skittles: Approximately 1.5-2 mL per piece (let's take an average of 1.75 mL)
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Total volume for the jar: The total volume of the jar is 1600 mL, but since you're counting the chocolates on the sides and not full pieces, we need to adjust our estimate based on your observation of 14 or 15 chocolates per side. Assuming "sides" means the outer layer and you have one layer of chocolates visible on the jar sides, we will multiply that number by 4 (for all sides).
Let's use 15 chocolates per side for calculation purposes: \[ \text{Total chocolates visible} = 15 \text{ chocolates per side} \times 4 \text{ sides} = 60 \text{ chocolates} \]
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Estimate the volume for the chocolates: Since you are predicting 14 or 15 chocolates per side, we can assume that if they fit well, they'll take up a significant amount of volume. To estimate chocolates inside, let's calculate how much space is left after accounting for the chocolates on the side.
If we assume 60 visible pieces occupy the sides (let's say they take up about 50 mL combined): \[ \text{Total volume used} = 50 \text{ mL} \] \[ \text{Volume remaining for chocolates} = 1600 \text{ mL} - 50 \text{ mL} = 1550 \text{ mL} \]
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Calculate the number of additional chocolates inside: Let's do a rough calculation for each type of chocolate.
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For Aero or KitKat (12.5 mL each): \[ \text{Number of chocolates} = \frac{1550 \text{ mL}}{12.5 \text{ mL/chocolate}} \approx 124 \text{ chocolates} \]
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For Skittles (1.75 mL each): \[ \text{Number of Skittles} = \frac{1550 \text{ mL}}{1.75 \text{ mL/skittle}} \approx 885 \text{ Skittles} \]
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Total found chocolates: If you decide to go with only one type of chocolate, and for example, you would have about 124 Aero or KitKat alongside the visible 60 chocolates.
- Total for KitKat or Aero: 124 + 60 = 184 candies.
- Total for Skittles: 885 (Skittles would not mix with Aero or KitKat).
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Boxes Required: Depending on how many pieces there are in boxes, let's assume:
- Aero: 8 pieces per box
- KitKat: 4 fingers per pack (2 bars per box, so approx. 8 fingers)
- Skittles: 18 pieces per pack
Using these assumptions:
- For KitKat or Aero: \[ \frac{184}{8} \approx 23 \text{ boxes of Aero or KitKat} \]
- For Skittles: \[ \frac{885}{18} \approx 49 \text{ packs of Skittles} \]
In conclusion, based on your estimation and counting chocolates per side, you would need approximately 23 boxes of Aero or KitKat or around 49 packs of Skittles to fill the jar adequately. Adjust these estimates based on the actual chocolates' packaging and volume.