How much chocolates (aero, kitkate, skittles) would be inside a about 1600 ML jar and if I counted (predicted about) 14/15 chocolates per side (not counted the inside) How many?

1 answer

To estimate how many chocolates would fit inside a 1600 mL jar, we need to consider the average size of the chocolates you mentioned (Aero, KitKat, and Skittles).

  1. Assume average sizes:

    • Aero: Approximately 20 mL per bar (3.5g).
    • KitKat: Approximately 10 mL per bar (around 1.5g per stick).
    • Skittles: Approximately 0.1 mL per piece.
  2. Count of chocolates per side: If you counted (predicted about) 14/15 chocolates per side, let's say we're considering a jar where we can see chocolates on two sides (the front and the back). Therefore, you would see around \(14 + 14 = 28\) chocolates per viewing side (assuming they are layered).

  3. Estimate total volume taken up by these chocolates:

    • For example, if you use Skittles:

      • Each Skittle is 0.1 mL.
      • 28 Skittles would take up about \(28 \times 0.1 = 2.8\) mL, which is a very small amount compared to the volume of the jar.
    • Using larger chocolates like Aero or KitKat, let’s say you go with KitKat for this estimation:

      • If you estimate 28 chocolates at an average of 10 mL each (for KitKat), it would be \(28 \times 10 = 280\) mL.
  4. Total estimated chocolates in the entire jar: Let’s consider packing efficiency and filling the jar:

    • The volume of the jar is 1600 mL.
    • If the jar holds chocolates that are both small and large and potentially fits better due to shape, we can downscale the packing maximum capacity.
    • A rough packing efficiency could be around 70% (due to air gaps), meaning the effective volume for chocolates could be around \(1600 \times 0.7 = 1120\) mL.
  5. Total estimation:

    • For KitKat: If we take 10 mL per chocolate (280 chocolates): \[ \text{Number of KitKats} = \frac{1120 , \text{mL}}{10 , \text{mL/chocolate}} = 112 \text{ chocolates} \]

    • For Aero (20 mL each): \[ \text{Number of Aeros} = \frac{1120}{20} = 56 , \text{Aeros} \]

    • For Skittles (0.1 mL each): \[ \text{Number of Skittles} = \frac{1120}{0.1} = 11200 , \text{Skittles} \]

Depending on the type of chocolate you choose, the estimate for how many would fit into a 1600 mL jar can be vastly different. Choose the specific type and you can gather a more precise count! In summary, you could potentially fit about 112 KitKats, 56 Aeros, or 11200 Skittles in a 1600 mL jar.