capacitance = charge per unit voltage (by definition)
C = Q/V
2 * 10^-6 = Q/12
so
Q = 24*10^-6 Coulombs
How much charge flows through a 12 –V battery when a 2.0 mF capacitor is connected across its terminals?
3 answers
Capacitance = Charge stored per unit voltage:
C = Q/V
So Charge Stored across capacitor:
Q = C*V
Charge stored across capacitor = Charge flow across battery:
2.0mF = 2*10^-3 F
2*10^-3 (F) * 12 (V) = 2.4*10^-2 C
C = Q/V
So Charge Stored across capacitor:
Q = C*V
Charge stored across capacitor = Charge flow across battery:
2.0mF = 2*10^-3 F
2*10^-3 (F) * 12 (V) = 2.4*10^-2 C
C = Q/V
Q = C . V
Q = ( 2 . 10 ^-6 ) * 12
Q = 0.000024 C
Q = C . V
Q = ( 2 . 10 ^-6 ) * 12
Q = 0.000024 C