How much Ba(OH)2 is needed to neutralize 3.2 moles of H2SO4 and 4.5 moles of HCl mixed together in 755 mL of water?

Answer 1

Moles of H+ ions: 3.2*.755*2+ 4.5*.755
= .755(6.4+4.5)

moles of Ba(OH)2= 1/2 (moles H+ ions).

Answer 2

I am still a little confused, how did you get the .755(6.4+4.5)?

Answer 3

Look at the line above. I figured the moles from the two acids and added.

Answer 4

why did you multiply by .755 when we were given moles not molarity?