How much absolute (total) pressure must a submarine withstand at a depth of 120m in the lake. Give answer in kPa. (Use 10m/s^2 for g).
h=120m
p_water = 1 g/cm^3 = 1000 kg/m^3
p_atmosphere = 101.3kPa
P_total = ?
P_water =density *g*h
=1000*10*120
=1200000Pa
=1200kPa
P_total =1200 kPa +101.3 kPa= 1301.3 kPa
Did I convert correctly for the density of water and from Pa to kPa?Thanks for your help.
1 answer
Yes, you converted correctly. The total pressure that a submarine must withstand at a depth of 120m in the lake is 1301.3 kPa.