In a neutral Sm atom (Z = 62), the electron configuration is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^6 5d^0 6p^0
To determine the number of unpaired electrons, we need to consider the last electron added, which is the 4f^6 electron. The 4f sublevel can hold a maximum of 14 electrons, so there are 8 electrons already paired up in the 4f orbital.
Thus, there are 6 unpaired electrons in a neutral Sm atom (Z = 62).
To write the electron configuration of the +3 ion, we remove 3 electrons from the neutral atom. Removing electrons from the outermost (highest energy) shell first, we will remove the 6s^2 electrons and one 4f^6 electron.
Therefore, the electron configuration of the Sm+3 ion is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 4f^5
How many unpaired electrons are in Sm where z= 62 write the electrons configuration of +3 ion
3 answers
The alloy SmCo5 forms a permanent magnet because both samarium and cobalt have unpaired electrons. a)How many unpaired electrons are in Sm where z= 62 b)write the electrons configuration of +3 ion
a) In a Sm atom (Z = 62), the electron configuration is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^6 5d^0 6p^0
To determine the number of unpaired electrons, we need to consider the last electron added, which is the 4f^6 electron. The 4f sublevel can hold a maximum of 14 electrons, so there are 8 electrons already paired up in the 4f orbital.
Thus, there are 6 unpaired electrons in a Sm atom (Z = 62).
b) To write the electron configuration of the +3 ion, we remove 3 electrons from the neutral atom. Removing electrons from the outermost (highest energy) shell first, we will remove the 6s^2 electrons and one 4f^6 electron.
Therefore, the electron configuration of the Sm+3 ion is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 4f^5
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^6 5d^0 6p^0
To determine the number of unpaired electrons, we need to consider the last electron added, which is the 4f^6 electron. The 4f sublevel can hold a maximum of 14 electrons, so there are 8 electrons already paired up in the 4f orbital.
Thus, there are 6 unpaired electrons in a Sm atom (Z = 62).
b) To write the electron configuration of the +3 ion, we remove 3 electrons from the neutral atom. Removing electrons from the outermost (highest energy) shell first, we will remove the 6s^2 electrons and one 4f^6 electron.
Therefore, the electron configuration of the Sm+3 ion is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 4f^5