CuSO4.5H2O ==> Cu^+2 + SO4^- + 5H2O
Convert 3.70 g CuSO4.5H2O to mols CuSO4.5H2O. Then for each mol of the starting material, you obtain 1 mol Cu^+2 ions and 1 mol SO4^-2 ions. Add those together to find the total mols. I've not added the H2O since that doesn't ionize (at least not that much).
How many total moles of ions are released when each of the following samples dissolves completely in water? ?
3.70g of CuSO4 5H2O
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1 answer