To find out how many times the highest common factor (HCF) of two numbers is contained in their lowest common multiple (LCM), we can use the following formula:
LCM(a, b) = (a * b) / HCF(a, b)
Given that the HCF of 64 and 126 is 2, we can substitute this value into the formula:
LCM(64, 126) = (64 * 126) / 2
LCM(64, 126) = 8064 / 2
LCM(64, 126) = 4032
Therefore, the HCF of 64 and 126 is contained in their LCM 4032/2 = <<4032/2=2016>>2016 times.
How many times of HCF of 64 and 126 contained in their LCM?
1 answer