How many terms of a series 13+10+7+... amounts to 28
3 answers
The answer is 4 terms.
How many terms of the series 7+10+13+.... Amounts to 87
The original question was once again missed by the bot.
Clearly, the 1st 4 terms add up to 34
It can be solved using
n/2 (2*13 - (n-1)*3) = 28
so n=7
The revised problem can be written as
n/2 (2*7 + (n-1)*3) = 87
so n = 6
Clearly, the 1st 4 terms add up to 34
It can be solved using
n/2 (2*13 - (n-1)*3) = 28
so n=7
The revised problem can be written as
n/2 (2*7 + (n-1)*3) = 87
so n = 6
1 answer