How many terms are there In an arithmetic Sequence with a common different of 4 and with the first and last term 3 and 59 Respectively.

Answer 1

Let Common difference = d =4
First term= a -3
Last term = l = 59
And number of terms = n

l=a+(n-1)d
59= 3 + (n-1)4
59=3+4n-4
59=4n-1
60=4n
60/4 =n
15=n

#There are 15 terms in the sequence