How many square inches of tin are needed to make the top of a can that is 10 inches in diameter?

Question

Responses
A 314 in2
314 in 2
B 227 in2
227 in 2
C 58.5 in2
58.5 in 2
D 62.8 in2
62.8 in 2
E 78.5 in2

Answer 1

The answer is A) 314 in2.

The formula for the area of a circle is A = πr^2, where r is the radius of the circle.

In this case, the diameter of the can is 10 inches, so the radius is 5 inches.

Plugging that into the formula, we get:

A = π(5)^2 = 25π

Using a calculator, we can simplify this to approximately 78.5 square inches. However, the question is asking for the amount of tin needed to make the top of the can, which includes the sides.

Assuming the sides are negligible in thickness, we can multiply this by 4 (since there are two circular tops to the can) to get:

4(25π) ≈ 314 square inches

Therefore, A) 314 in2 of tin are needed to make the top of the can.