The given system of equations is:
-3x + 6y = 10 ...(1)
-3x + 6y = -4 ...(2)
If we subtract equation (2) from equation (1), we can see that both sides of the equation will cancel out:
-3x + 6y - (-3x + 6y) = 10 - (-4)
-3x + 3x + 6y - 6y = 10 + 4
0 = 14
This equation is not possible, as there is no number that can satisfy it. Therefore, the system of equations has no solution.
Hence, the answer is: none.
How many solutions does this system have?
-3x + 6y = 10
-3x + 6y = -4
(1 point)
none
one
infinite
two
1 answer