how many solutions does this equation have?

13b + 18 = 17b - 6 - 16b

1 answer

To find how many solutions the equation \( 13b + 18 = 17b - 6 - 16b \) has, we can start by simplifying the equation:

  1. Combine like terms on the right side: \[ 17b - 16b = b \] Thus, the equation becomes: \[ 13b + 18 = b - 6 \]

  2. Next, we isolate \( b \) by subtracting \( b \) from both sides: \[ 13b - b + 18 = -6 \] Simplifying the left side gives: \[ 12b + 18 = -6 \]

  3. Now, subtract 18 from both sides: \[ 12b = -6 - 18 \] Thus, \[ 12b = -24 \]

  4. Finally, divide both sides by 12: \[ b = \frac{-24}{12} = -2 \]

Since we obtained a single value for \( b \), the equation has one solution: \( b = -2 \).