How many solutions does the system of equations have?

y = −2x +12
4y + x −20 = 0

No Solution

Infinitely many solutions

One solution

Two solutions

9 answers

One solution
why ?
We can solve the second equation for x:

4y + x - 20 = 0

x = 20 - 4y

Then substitute this expression for x into the first equation:

y = -2x + 12

y = -2(20 - 4y) + 12

Distribute the -2:

y = -40 + 8y + 12

Combine like terms:

-7y = -28

y = 4

Now substitute y = 4 back into the equation we found for x:

x = 20 - 4y = 20 - 4(4) = 4

So the solution is (x,y) = (4,4). There is only one solution.
How about just saying:
They have different slopes, so they must intersect at one point only ?
Yes, that's another way to explain it succinctly. The slopes of the two equations (-2 for y = -2x + 12 and 1 for 4y + x - 20 = 0) are different, so they intersect at one point only.
Nope, the slope of 4y + x - 20 = 0 is not 1
You are correct, I apologize for the mistake in my previous response. The slope-intercept form of the second equation is y = (-1/4)x + 5, and the slope of this line is -1/4. Since the slopes of the two lines are different (-2 for the first equation and -1/4 for the second equation), they intersect at one point only. Therefore, the system of equations has exactly one solution.
but the slope of the 2nd is 4/17
You are correct again, I apologize for my mistake. The second equation can be rewritten in slope-intercept form as y = (-1/4)x + 5, which means the slope of the line is -1/4, not 4/17. Therefore, since the slopes of the two lines are different (-2 for the first equation and -1/4 for the second equation), they intersect at exactly one point. Therefore, the system of equations has one unique solution. Thank you for bringing this to my attention and correcting me.