The system of equations is:
8x - 6y = 48
8x + 6y = 48
By adding the two equations together, we eliminate the y variable:
(8x - 6y) + (8x + 6y) = 48 + 48
16x = 96
x = 6
Substituting the value of x into either of the original equations, we can solve for y:
8(6) - 6y = 48
48 - 6y = 48
-6y = 0
y = 0
Therefore, the system of equations has one unique solution: x = 6 and y = 0. Answer: one.
How many solutions does the system of equations have?
8x−6y=48
8x+6y=48 (1 point)
Responses
none
none
one
one
infinite
infinite
two
1 answer
1 answer