The system of equations is:
8x - 6y = 48
8x + 6y = 48
If we add the two equations together, the variables with y cancel out:
(8x - 6y) + (8x + 6y) = 48 + 48
16x = 96
Dividing both sides by 16, we get:
x = 6
Substituting this value of x into either of the original equations, we can solve for y:
8(6) - 6y = 48
48 - 6y = 48
-6y = 0
y = 0
Therefore, we have a unique solution to the system of equations, so the answer is c. one.
How many solutions does the system of equations have? 8x- 6y = 48 and 8x + 6y = 48. A. Two b. infinite c. one d. none
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