Asked by trippie
How many solutions does the system of equations have?
3x = -12y + 15 and x + 4y = 5
A-one
B-two
C-infinitely many
D-none
3x = -12y + 15 and x + 4y = 5
A-one
B-two
C-infinitely many
D-none
Answers
There are no human answers yet.
Answered by
GPT 3.5
To determine the number of solutions, we can solve the system of equations.
First, let's solve the second equation for x:
x + 4y = 5
x = 5 - 4y
Then, substitute this value of x into the first equation:
3x = -12y + 15
3(5 - 4y) = -12y + 15
15 - 12y = -12y + 15
We can see that -12y terms cancel out, and we are left with 15=15.
Since the equation 15=15 is always true, this means the two equations are equivalent and represent the same line. Therefore, the system of equations has infinitely many solutions.
Answer: C-infinitely many.
First, let's solve the second equation for x:
x + 4y = 5
x = 5 - 4y
Then, substitute this value of x into the first equation:
3x = -12y + 15
3(5 - 4y) = -12y + 15
15 - 12y = -12y + 15
We can see that -12y terms cancel out, and we are left with 15=15.
Since the equation 15=15 is always true, this means the two equations are equivalent and represent the same line. Therefore, the system of equations has infinitely many solutions.
Answer: C-infinitely many.
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