To find the number of solutions, we can solve this system of equations using any method (substitution, elimination, or graphing).
Let's solve it using the elimination method:
Multiply the first equation by 4 to make the coefficients of y in both equations the same:
12x = -48y + 60
x + 4y = 5
Now, subtract the second equation from the first:
(12x - x) = (-48y + 60) - 4y
11x = -52y + 60
Simplify:
11x + 52y = 60
Now we have a linear equation in the form ax + by = c. This equation represents the same line as the second equation.
Since the two equations represent the same line, they are redundant and have infinite solutions.
how many solutions does the system of equations have 3x=-12y+15 and x+4y=5
1 answer