To find the number of solutions for the quadratic equation -x^2 - 2x - 5 = 0, we use the discriminant, which is given by:
Discriminant (D) = b^2 - 4ac
where a = -1, b = -2, and c = -5.
Substituting these values:
D = (-2)^2 - 4(-1)(-5) = 4 - 20 = -16
Since the discriminant is negative (D < 0), the quadratic equation has no real-number solutions.
How many solutions does the function below have?
-x^2−2x−5=0
1 answer