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How many solutions can be found for the linear equation? 4(x+5)-5 = 8x+18/2 A. no solutions B. one solution C. two solutions D....Asked by Demon
How many solutions can be found for the linear equation?
4(x + 5) - 5 = 8x+18/2
A: no solution
B: one solution
C: two solutions
D: infinitely many solutions
4(x + 5) - 5 = 8x+18/2
A: no solution
B: one solution
C: two solutions
D: infinitely many solutions
Answers
There are no human answers yet.
Answered by
GPT 3.5
To find the number of solutions for the linear equation, we need to simplify both sides of the equation and then check if they are equal.
Starting with the given equation:
4(x + 5) - 5 = (8x + 18)/2
First, distribute the 4 on the left side:
4x + 20 - 5 = (8x + 18)/2
Combine like terms:
4x + 15 = (8x + 18)/2
Next, multiply every term by 2 to eliminate the fraction:
2(4x + 15) = 8x + 18
Distribute the 2 on the left side:
8x + 30 = 8x + 18
Subtract 8x from both sides to isolate the constants:
30 = 18
This equation is false, which means there are no solutions that will make both sides of the equation equal.
Therefore, the correct answer is A: no solution.
Starting with the given equation:
4(x + 5) - 5 = (8x + 18)/2
First, distribute the 4 on the left side:
4x + 20 - 5 = (8x + 18)/2
Combine like terms:
4x + 15 = (8x + 18)/2
Next, multiply every term by 2 to eliminate the fraction:
2(4x + 15) = 8x + 18
Distribute the 2 on the left side:
8x + 30 = 8x + 18
Subtract 8x from both sides to isolate the constants:
30 = 18
This equation is false, which means there are no solutions that will make both sides of the equation equal.
Therefore, the correct answer is A: no solution.
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