4 y = x + 8
y = -54 x - 4
4 y = x + 8
4y = -216 x -16
so
x+8 = -216 x - 16
217 x = -24
x = -24/217
then y = -54 x - 4
Those lines only hit once :)
How many solutions are there to the following system of equations?
−8=−4y+x
−54x=y+4
3 answers
Write first equation as:
4 y = - x - 8
Divide both sides by 4
y = - x / 4 - 2 = - 1 / 4 x - 2
Write second equation as:
y = - 54 x - 4
The gradient of first line:
m1 = - 1 / 4
The gradient of second line:
m2 = - 54
Two straight line with different gradients have only one point of intersection.
So you system have one solution.
4 y = - x - 8
Divide both sides by 4
y = - x / 4 - 2 = - 1 / 4 x - 2
Write second equation as:
y = - 54 x - 4
The gradient of first line:
m1 = - 1 / 4
The gradient of second line:
m2 = - 54
Two straight line with different gradients have only one point of intersection.
So you system have one solution.
My typo.
Write first equation as:
4 y = x + 8
Divide both sides by 4
y = x / 4 + 2 = 1 / 4 x + 2
Write second equation as:
y = - 54 x - 4
The gradient of first line:
m1 = 1 / 4
The gradient of second line:
m2 = - 54
Two straight line with different gradients have only one point of intersection.
So you system have one solution.
Write first equation as:
4 y = x + 8
Divide both sides by 4
y = x / 4 + 2 = 1 / 4 x + 2
Write second equation as:
y = - 54 x - 4
The gradient of first line:
m1 = 1 / 4
The gradient of second line:
m2 = - 54
Two straight line with different gradients have only one point of intersection.
So you system have one solution.
1 answer