2 [ 1/4 ( 4 y - 8 ) + 3 y ] = 3 ( y + 1 ) + 5 y
2 ( 1/4 ∙ 4 y - 1/4 ∙ 8 + 3 y ) = 3 y + 3 + 5 y
2 ( y - 2 + 3 y ) = 8 y + 3
2 y - 4 + 6 y = 8 y + 3
8 y - 4 = 8 y + 3
Again that is a system of equations that graphs as parallel lines, there can be no solution.
0 solutions.
How many solutions are there for the equation:
2[ 1/4 (4y - 8) + 3y] = 3(y + 1) + 5y
2 answers
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