To solve the equation \( 2x^2 = 20 \), we can start by simplifying it.
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Divide both sides by 2: \[ x^2 = 10 \]
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Next, take the square root of both sides: \[ x = \pm\sqrt{10} \]
This indicates that there are two solutions: \( x = \sqrt{10} \) and \( x = -\sqrt{10} \).
So the number of solutions in the solution set is two.
The answer is A. Two.