To determine how many solutions each quadratic equation has, we can analyze each equation.
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For the equation \(5x^2 = 50\):
- First, divide both sides by 5: \[ x^2 = 10 \]
- The solutions for \(x\) can be found by taking the square root: \[ x = \pm \sqrt{10} \]
- Since there are two solutions (\(\sqrt{10}\) and \(-\sqrt{10}\)), this quadratic equation would have 2 solution(s).
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For the equation \(3x^2 = -12\):
- First, divide both sides by 3: \[ x^2 = -4 \]
- Since the right side is negative, there are no real solutions (the square of a real number cannot be negative). Thus, the solutions are complex: \[ x = \pm 2i \]
- Since there are two complex solutions, this quadratic equation would have 2 solution(s).
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For the equation \(8x^2 = 0\):
- Divide both sides by 8: \[ x^2 = 0 \]
- The only solution is: \[ x = 0 \]
- Since there's only one unique solution (counting multiplicity), this quadratic equation would have 1 solution(s).
Summary:
- \(5x^2 = 50\) would have 2 solution(s).
- \(3x^2 = -12\) would have 2 solution(s).
- \(8x^2 = 0\) would have 1 solution(s).