How many solution are in the solution set for the equation: 2x^2 = 20

Answer 1

To find the number of solutions for the equation \(2x^2 = 20\), we can start by simplifying the equation.

1. Divide both sides by 2:

\[ x^2 = 10 \]

2. Next, take the square root of both sides. Remember that taking the square root gives us both the positive and negative solutions:

\[ x = \pm \sqrt{10} \]

Thus, there are two solutions for the equation \(2x^2 = 20\):

1. \(x = \sqrt{10}\)
2. \(x = -\sqrt{10}\)

Therefore, the number of solutions in the solution set for the equation \(2x^2 = 20\) is \(\boxed{2}\).