Asked by joshuah
how many side and angles does a trapezoid angle, hexagon, and pentagon have?
solve each equation:
13 + y = -3, 3y + 8=3, y over 3= -9
need help with + & - rules for adding whole numbers, decimals, fractions and integers ( do not understand) and rule for multiplying + & -
solve each equation:
13 + y = -3, 3y + 8=3, y over 3= -9
need help with + & - rules for adding whole numbers, decimals, fractions and integers ( do not understand) and rule for multiplying + & -
Answers
Answered by
Damon
Google the fist question
hint --- hex means 6 and pent means five
13 + y = -3
-13 = -13 add
-----------------
13-13 + y = -16
y = -16
=============================
3y + 8=3
-8 = -8 add
---------------
3 y + 0 = -5
y = -5/3
=============================
y over 3= -9
3 (y/3) = 3 (-9)
y = -18
hint --- hex means 6 and pent means five
13 + y = -3
-13 = -13 add
-----------------
13-13 + y = -16
y = -16
=============================
3y + 8=3
-8 = -8 add
---------------
3 y + 0 = -5
y = -5/3
=============================
y over 3= -9
3 (y/3) = 3 (-9)
y = -18
Answered by
joshuah
sorry i do not understand. this is 6th grade math. i am suppose to solve for y. not change what it is equal to.
13 + y = -3
13 + y = -3
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